Given hexagon ABCDEF with A(1,6), B(3,9), C(6,9),
D(8,6), E( 6,3), and F(3,3).
Find the number of square units in the area of ABCDEF.
Solution: The "box method" will work nicely.
A_{Box} = A_{Δ1} + A_{Δ2} + A_{Δ3} + A_{Δ4} + A_{poly}
42 = 3 + 3 + 3 + 3 + A_{poly}
A_{poly}= 30 square units

