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Starting with this lesson, we will be investigating angles, associated with circles,
whose measurement formulas are theorems.
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A inscribed angle of a circle is an angle whose vertex is a point on the circle and whose rays contain two other points on the circle (that is, the rays are chords). |
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Inscribed Angle (theorem)
The measure of an inscribed angle equals
½ the measure of its intercepted arc.
Inscribed Angle = Intercepted Arc
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In the diagram at the right, ∠ABC is an inscribed angle with an intercepted minor arc from A to C.
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m∠ABC = 41º |
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Example 1:
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How many inscribed angles can
be seen in this diagram?
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Solution:
• If the arc is 48º, then the inscribed angle, m∠ABD = 24º.
• If m∠BDC = 56º, then the minor arc from B to C has a measure of 112º. Since ∠BAC also intercepts this arc, m∠BAC = 56º.
• In ΔBAF we have angles of 56º and 24º, making m∠AFB = 100º
• Since ∠BFC is supplementary to∠AFB,
m∠BFC = 80º.
There are 8 inscribed angles.
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Example 2:
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Solution:
• With the given diameter, there are two semicircles. ∠A and ∠C are right angles.
• m∠BDC = ½ m of the minor arc from B to C.
(21 is half of 42)
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since 42 + 138 = 180 for the semicircle arc
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For the arc: 180 - 124 = 56
For the angle: ½ of 56 = 28
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Theorems Associated with Inscribed Angles:
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In a circle, inscribed angles that intercept the same arc are congruent. |
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Additional Theorems related to cyclic quadrilaterals:
• A cyclic parallelogram is a rectangle.
• If a pair of opposite sides of a cyclic quadrilateral are equal in length,
then the diagonals are also equal in length.
• The measure of the exterior angle of a cyclic quadrilateral is equal
to the measure of the interior opposite angle.
• In a cyclic quadrilateral, the product of the diagonals equals
the sum of the products of its two pairs of opposite sides.
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PROOF of the theorem on measuring an inscribed angle:
There are actually three cases for the proof of this theorem.
CASE 1: the center of the circle lies on one of the inscribed angle's rays (one ray is a diameter)
CASE 2: the center of the circle lies in the interior of the inscribed angle
CASE 3: the center of the circle does not lie in the interior of the inscribed angle
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